Base | Representation |
---|---|
bin | 1001100011110010… |
… | …11101101000000101 |
3 | 111020122222102111111 |
4 | 10301321131220011 |
5 | 41002310130222 |
6 | 2205131005021 |
7 | 241115152522 |
oct | 46171355005 |
9 | 14218872444 |
10 | 5132114437 |
11 | 21a3a4359a |
12 | bb2899771 |
13 | 63a337908 |
14 | 369852149 |
15 | 200851777 |
hex | 131e5da05 |
5132114437 has 2 divisors, whose sum is σ = 5132114438. Its totient is φ = 5132114436.
The previous prime is 5132114431. The next prime is 5132114467. The reversal of 5132114437 is 7344112315.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4408827201 + 723287236 = 66399^2 + 26894^2 .
It is a cyclic number.
It is not a de Polignac number, because 5132114437 - 211 = 5132112389 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5132114399 and 5132114408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5132114431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2566057218 + 2566057219.
It is an arithmetic number, because the mean of its divisors is an integer number (2566057219).
Almost surely, 25132114437 is an apocalyptic number.
It is an amenable number.
5132114437 is a deficient number, since it is larger than the sum of its proper divisors (1).
5132114437 is an equidigital number, since it uses as much as digits as its factorization.
5132114437 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10080, while the sum is 31.
The square root of 5132114437 is about 71638.7774672349. Note that the first 3 decimals coincide. The cubic root of 5132114437 is about 1724.9060439759.
The spelling of 5132114437 in words is "five billion, one hundred thirty-two million, one hundred fourteen thousand, four hundred thirty-seven".
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