Base | Representation |
---|---|
bin | 100101010101111000011… |
… | …0101001010111001000111 |
3 | 200011122012000212022220011 |
4 | 1022223300311022321013 |
5 | 1133041302220442021 |
6 | 14525414202451051 |
7 | 1036535323204435 |
oct | 112536065127107 |
9 | 20148160768804 |
10 | 5132231421511 |
11 | 16a96269276a7 |
12 | 6aa7b1b03a87 |
13 | 2b2c7634c44c |
14 | 13a58934bd55 |
15 | 8d77b40bde1 |
hex | 4aaf0d4ae47 |
5132231421511 has 2 divisors, whose sum is σ = 5132231421512. Its totient is φ = 5132231421510.
The previous prime is 5132231421479. The next prime is 5132231421563. The reversal of 5132231421511 is 1151241322315.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5132231421511 - 25 = 5132231421479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5132231421571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2566115710755 + 2566115710756.
It is an arithmetic number, because the mean of its divisors is an integer number (2566115710756).
Almost surely, 25132231421511 is an apocalyptic number.
5132231421511 is a deficient number, since it is larger than the sum of its proper divisors (1).
5132231421511 is an equidigital number, since it uses as much as digits as its factorization.
5132231421511 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7200, while the sum is 31.
Adding to 5132231421511 its reverse (1151241322315), we get a palindrome (6283472743826).
The spelling of 5132231421511 in words is "five trillion, one hundred thirty-two billion, two hundred thirty-one million, four hundred twenty-one thousand, five hundred eleven".
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