Base | Representation |
---|---|
bin | 1001100011110100… |
… | …10111001010100101 |
3 | 111020200102101210101 |
4 | 10301322113022211 |
5 | 41002340200432 |
6 | 2205140024101 |
7 | 241120153606 |
oct | 46172271245 |
9 | 14220371711 |
10 | 5132350117 |
11 | 21a4094674 |
12 | bb2992031 |
13 | 63a3bac7b |
14 | 3698b3dad |
15 | 20089b4e7 |
hex | 131e972a5 |
5132350117 has 2 divisors, whose sum is σ = 5132350118. Its totient is φ = 5132350116.
The previous prime is 5132350063. The next prime is 5132350121. The reversal of 5132350117 is 7110532315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3576757636 + 1555592481 = 59806^2 + 39441^2 .
It is a cyclic number.
It is not a de Polignac number, because 5132350117 - 211 = 5132348069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5132350127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2566175058 + 2566175059.
It is an arithmetic number, because the mean of its divisors is an integer number (2566175059).
Almost surely, 25132350117 is an apocalyptic number.
It is an amenable number.
5132350117 is a deficient number, since it is larger than the sum of its proper divisors (1).
5132350117 is an equidigital number, since it uses as much as digits as its factorization.
5132350117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3150, while the sum is 28.
The square root of 5132350117 is about 71640.4223675433. The cubic root of 5132350117 is about 1724.9324476242.
The spelling of 5132350117 in words is "five billion, one hundred thirty-two million, three hundred fifty thousand, one hundred seventeen".
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