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513307396841 is a prime number
BaseRepresentation
bin1110111100000111000…
…00010100101011101001
31211001221021102111220012
413132003200110223221
531402223143144331
61031450554541305
752041143611601
oct7360340245351
91731837374805
10513307396841
11188768709728
1283595737835
133953510a2a5
141abb6729c01
15d54405582b
hex7783814ae9

513307396841 has 2 divisors, whose sum is σ = 513307396842. Its totient is φ = 513307396840.

The previous prime is 513307396817. The next prime is 513307396843. The reversal of 513307396841 is 148693703315.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 487756972816 + 25550424025 = 698396^2 + 159845^2 .

It is a cyclic number.

It is not a de Polignac number, because 513307396841 - 210 = 513307395817 is a prime.

Together with 513307396843, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 513307396841.

It is not a weakly prime, because it can be changed into another prime (513307396843) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256653698420 + 256653698421.

It is an arithmetic number, because the mean of its divisors is an integer number (256653698421).

Almost surely, 2513307396841 is an apocalyptic number.

It is an amenable number.

513307396841 is a deficient number, since it is larger than the sum of its proper divisors (1).

513307396841 is an equidigital number, since it uses as much as digits as its factorization.

513307396841 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1632960, while the sum is 50.

The spelling of 513307396841 in words is "five hundred thirteen billion, three hundred seven million, three hundred ninety-six thousand, eight hundred forty-one".