Base | Representation |
---|---|
bin | 10111010101111101100010… |
… | …00110001001011111000101 |
3 | 20201202022012001222202010122 |
4 | 23222332301012021133011 |
5 | 23212011143041132240 |
6 | 301101353002231325 |
7 | 13545423630060005 |
oct | 1352766106113705 |
9 | 221668161882118 |
10 | 51332125333445 |
11 | 153a0917585830 |
12 | 5910614ab5545 |
13 | 22847a2300258 |
14 | c966b95a0005 |
15 | 5e03ee07c4b5 |
hex | 2eafb11897c5 |
51332125333445 has 32 divisors (see below), whose sum is σ = 68631988248576. Its totient is φ = 36536115553600.
The previous prime is 51332125333439. The next prime is 51332125333453. The reversal of 51332125333445 is 54433352123315.
It is not a de Polignac number, because 51332125333445 - 24 = 51332125333429 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 51332125333396 and 51332125333405.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 46728950 + ... + 47814840.
It is an arithmetic number, because the mean of its divisors is an integer number (2144749632768).
Almost surely, 251332125333445 is an apocalyptic number.
51332125333445 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
51332125333445 is a deficient number, since it is larger than the sum of its proper divisors (17299862915131).
51332125333445 is a wasteful number, since it uses less digits than its factorization.
51332125333445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1104241.
The product of its digits is 1944000, while the sum is 44.
The spelling of 51332125333445 in words is "fifty-one trillion, three hundred thirty-two billion, one hundred twenty-five million, three hundred thirty-three thousand, four hundred forty-five".
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