Base | Representation |
---|---|
bin | 101111110011110000… |
… | …000110111111010001 |
3 | 11220111120012020201221 |
4 | 233303300012333101 |
5 | 1320113013142111 |
6 | 35325500125041 |
7 | 3465051531451 |
oct | 576360067721 |
9 | 156446166657 |
10 | 51334115281 |
11 | 1a852851669 |
12 | 9b47836781 |
13 | 4ac1290b57 |
14 | 26ad9b1d61 |
15 | 1506a73371 |
hex | bf3c06fd1 |
51334115281 has 2 divisors, whose sum is σ = 51334115282. Its totient is φ = 51334115280.
The previous prime is 51334115269. The next prime is 51334115323. The reversal of 51334115281 is 18251143315.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40659092881 + 10675022400 = 201641^2 + 103320^2 .
It is a cyclic number.
It is not a de Polignac number, because 51334115281 - 25 = 51334115249 is a prime.
It is a super-2 number, since 2×513341152812 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51334115221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25667057640 + 25667057641.
It is an arithmetic number, because the mean of its divisors is an integer number (25667057641).
Almost surely, 251334115281 is an apocalyptic number.
It is an amenable number.
51334115281 is a deficient number, since it is larger than the sum of its proper divisors (1).
51334115281 is an equidigital number, since it uses as much as digits as its factorization.
51334115281 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 14400, while the sum is 34.
Adding to 51334115281 its reverse (18251143315), we get a palindrome (69585258596).
The spelling of 51334115281 in words is "fifty-one billion, three hundred thirty-four million, one hundred fifteen thousand, two hundred eighty-one".
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