Base | Representation |
---|---|
bin | 111010010111101010011000… |
… | …1110111010001000100010111 |
3 | 2111022220000000101222200120021 |
4 | 1310233110301313101010113 |
5 | 1014243430432124240201 |
6 | 5015544232333450011 |
7 | 213100525031062462 |
oct | 16457246167210427 |
9 | 2438800011880507 |
10 | 513425522102551 |
11 | 1396585a52842a3 |
12 | 49701380640907 |
13 | 19063a85417166 |
14 | 90adcdc0982d9 |
15 | 3e555993d2ea1 |
hex | 1d2f531dd1117 |
513425522102551 has 2 divisors, whose sum is σ = 513425522102552. Its totient is φ = 513425522102550.
The previous prime is 513425522102543. The next prime is 513425522102561. The reversal of 513425522102551 is 155201225524315.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 513425522102551 - 23 = 513425522102543 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 513425522102498 and 513425522102507.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (513425522102501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256712761051275 + 256712761051276.
It is an arithmetic number, because the mean of its divisors is an integer number (256712761051276).
Almost surely, 2513425522102551 is an apocalyptic number.
513425522102551 is a deficient number, since it is larger than the sum of its proper divisors (1).
513425522102551 is an equidigital number, since it uses as much as digits as its factorization.
513425522102551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 600000, while the sum is 43.
Adding to 513425522102551 its reverse (155201225524315), we get a palindrome (668626747626866).
The spelling of 513425522102551 in words is "five hundred thirteen trillion, four hundred twenty-five billion, five hundred twenty-two million, one hundred two thousand, five hundred fifty-one".
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