Base | Representation |
---|---|
bin | 10111010110010010000010… |
… | …01110101011000000001111 |
3 | 20201210100121020122120012201 |
4 | 23223021001032223000033 |
5 | 23212201214123442313 |
6 | 301110413155542331 |
7 | 13546263465220303 |
oct | 1353110116530017 |
9 | 221710536576181 |
10 | 51343133421583 |
11 | 153a5556338333 |
12 | 59127875ba9a7 |
13 | 2285837aca183 |
14 | c97041577d03 |
15 | 5e08456b80dd |
hex | 2eb2413ab00f |
51343133421583 has 2 divisors, whose sum is σ = 51343133421584. Its totient is φ = 51343133421582.
The previous prime is 51343133421533. The next prime is 51343133421617. The reversal of 51343133421583 is 38512433134315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51343133421583 - 241 = 49144110166031 is a prime.
It is a super-2 number, since 2×513431334215832 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51343133421533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25671566710791 + 25671566710792.
It is an arithmetic number, because the mean of its divisors is an integer number (25671566710792).
Almost surely, 251343133421583 is an apocalyptic number.
51343133421583 is a deficient number, since it is larger than the sum of its proper divisors (1).
51343133421583 is an equidigital number, since it uses as much as digits as its factorization.
51343133421583 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1555200, while the sum is 46.
Adding to 51343133421583 its reverse (38512433134315), we get a palindrome (89855566555898).
The spelling of 51343133421583 in words is "fifty-one trillion, three hundred forty-three billion, one hundred thirty-three million, four hundred twenty-one thousand, five hundred eighty-three".
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