Base | Representation |
---|---|
bin | 1001100100000100… |
… | …11100100110011101 |
3 | 111020211102002002021 |
4 | 10302002130212131 |
5 | 41003411011113 |
6 | 2205253300141 |
7 | 241144161634 |
oct | 46202344635 |
9 | 14224362067 |
10 | 5134469533 |
11 | 21a5301a56 |
12 | bb3634651 |
13 | 63a98086b |
14 | 369ca651b |
15 | 200b6948d |
hex | 13209c99d |
5134469533 has 2 divisors, whose sum is σ = 5134469534. Its totient is φ = 5134469532.
The previous prime is 5134469471. The next prime is 5134469603. The reversal of 5134469533 is 3359644315.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4950107449 + 184362084 = 70357^2 + 13578^2 .
It is a cyclic number.
It is not a de Polignac number, because 5134469533 - 213 = 5134461341 is a prime.
It is a super-3 number, since 3×51344695333 (a number of 30 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5134469533.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5134469233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2567234766 + 2567234767.
It is an arithmetic number, because the mean of its divisors is an integer number (2567234767).
Almost surely, 25134469533 is an apocalyptic number.
It is an amenable number.
5134469533 is a deficient number, since it is larger than the sum of its proper divisors (1).
5134469533 is an equidigital number, since it uses as much as digits as its factorization.
5134469533 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 583200, while the sum is 43.
The square root of 5134469533 is about 71655.2128808505. The cubic root of 5134469533 is about 1725.1698532460.
The spelling of 5134469533 in words is "five billion, one hundred thirty-four million, four hundred sixty-nine thousand, five hundred thirty-three".
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