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51345004546361 is a prime number
BaseRepresentation
bin10111010110010101100001…
…10000011100100100111001
320201210112102122111112212102
423223022300300130210321
523212214032130440421
6301111323000353145
713546361035424501
oct1353126060344471
9221715378445772
1051345004546361
11153a6326561049
12591300a1757b5
132285a756609b6
14c9717bc86a01
155e0904ac060b
hex2eb2b0c1c939

51345004546361 has 2 divisors, whose sum is σ = 51345004546362. Its totient is φ = 51345004546360.

The previous prime is 51345004546333. The next prime is 51345004546453. The reversal of 51345004546361 is 16364540054315.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 43292781075625 + 8052223470736 = 6579725^2 + 2837644^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51345004546361 is a prime.

It is not a weakly prime, because it can be changed into another prime (51345004546301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25672502273180 + 25672502273181.

It is an arithmetic number, because the mean of its divisors is an integer number (25672502273181).

Almost surely, 251345004546361 is an apocalyptic number.

It is an amenable number.

51345004546361 is a deficient number, since it is larger than the sum of its proper divisors (1).

51345004546361 is an equidigital number, since it uses as much as digits as its factorization.

51345004546361 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592000, while the sum is 47.

The spelling of 51345004546361 in words is "fifty-one trillion, three hundred forty-five billion, four million, five hundred forty-six thousand, three hundred sixty-one".