Base | Representation |
---|---|
bin | 10111010110011000000000… |
… | …11000010111101011011111 |
3 | 20201210122212202011120012021 |
4 | 23223030000120113223133 |
5 | 23212224301121142002 |
6 | 301112103320521011 |
7 | 13546436116204045 |
oct | 1353140030275337 |
9 | 221718782146167 |
10 | 51346340412127 |
11 | 153a6951625842 |
12 | 5913321620167 |
13 | 2285c29345807 |
14 | c97267462395 |
15 | 5e0981ee7737 |
hex | 2eb300617adf |
51346340412127 has 2 divisors, whose sum is σ = 51346340412128. Its totient is φ = 51346340412126.
The previous prime is 51346340412091. The next prime is 51346340412161. The reversal of 51346340412127 is 72121404364315.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51346340412127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51346340412187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25673170206063 + 25673170206064.
It is an arithmetic number, because the mean of its divisors is an integer number (25673170206064).
Almost surely, 251346340412127 is an apocalyptic number.
51346340412127 is a deficient number, since it is larger than the sum of its proper divisors (1).
51346340412127 is an equidigital number, since it uses as much as digits as its factorization.
51346340412127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 483840, while the sum is 43.
The spelling of 51346340412127 in words is "fifty-one trillion, three hundred forty-six billion, three hundred forty million, four hundred twelve thousand, one hundred twenty-seven".
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