Base | Representation |
---|---|
bin | 1110111100011110001… |
… | …00011001011111111101 |
3 | 1211002102210111001111102 |
4 | 13132033010121133331 |
5 | 31403122324400013 |
6 | 1031522125102445 |
7 | 52046020623605 |
oct | 7361704313775 |
9 | 1732383431442 |
10 | 513501403133 |
11 | 188858178504 |
12 | 8362a6b7a25 |
13 | 39566376404 |
14 | 1abd43cbc05 |
15 | d5560c8d58 |
hex | 778f1197fd |
513501403133 has 2 divisors, whose sum is σ = 513501403134. Its totient is φ = 513501403132.
The previous prime is 513501403117. The next prime is 513501403157. The reversal of 513501403133 is 331304105315.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 439777206649 + 73724196484 = 663157^2 + 271522^2 .
It is a cyclic number.
It is not a de Polignac number, because 513501403133 - 24 = 513501403117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 513501403096 and 513501403105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (513501403733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256750701566 + 256750701567.
It is an arithmetic number, because the mean of its divisors is an integer number (256750701567).
Almost surely, 2513501403133 is an apocalyptic number.
It is an amenable number.
513501403133 is a deficient number, since it is larger than the sum of its proper divisors (1).
513501403133 is an equidigital number, since it uses as much as digits as its factorization.
513501403133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8100, while the sum is 29.
Adding to 513501403133 its reverse (331304105315), we get a palindrome (844805508448).
The spelling of 513501403133 in words is "five hundred thirteen billion, five hundred one million, four hundred three thousand, one hundred thirty-three".
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