Base | Representation |
---|---|
bin | 10111010110011111111101… |
… | …11100010011000101000110 |
3 | 20201211001220101111021012212 |
4 | 23223033332330103011012 |
5 | 23212312022434241314 |
6 | 301114051203343422 |
7 | 13546650005523014 |
oct | 1353177674230506 |
9 | 221731811437185 |
10 | 51350611243334 |
11 | 153a8743380507 |
12 | 5914113981b72 |
13 | 228645a0c1480 |
14 | c975507558b4 |
15 | 5e0b31e18e3e |
hex | 2eb3fef13146 |
51350611243334 has 8 divisors (see below), whose sum is σ = 82950987393120. Its totient is φ = 23700282112296.
The previous prime is 51350611243307. The next prime is 51350611243381. The reversal of 51350611243334 is 43334211605315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 51350611243291 and 51350611243300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 987511754654 + ... + 987511754705.
It is an arithmetic number, because the mean of its divisors is an integer number (10368873424140).
Almost surely, 251350611243334 is an apocalyptic number.
51350611243334 is a deficient number, since it is larger than the sum of its proper divisors (31600376149786).
51350611243334 is a wasteful number, since it uses less digits than its factorization.
51350611243334 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1975023509374.
The product of its (nonzero) digits is 388800, while the sum is 41.
Adding to 51350611243334 its reverse (43334211605315), we get a palindrome (94684822848649).
The spelling of 51350611243334 in words is "fifty-one trillion, three hundred fifty billion, six hundred eleven million, two hundred forty-three thousand, three hundred thirty-four".
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