Base | Representation |
---|---|
bin | 111010011000010010110001… |
… | …0111110111001111000100101 |
3 | 2111100012021212022102110221220 |
4 | 1310300211202332321320211 |
5 | 1014301341034324043440 |
6 | 5020052134025530553 |
7 | 213110015103064656 |
oct | 16460454276717045 |
9 | 2440167768373856 |
10 | 513512245534245 |
11 | 1396913584050a1 |
12 | 49716144043a59 |
13 | 1906bcc646c509 |
14 | 90b41a7b5952d |
15 | 3e57972c898d0 |
hex | 1d30962fb9e25 |
513512245534245 has 64 divisors (see below), whose sum is σ = 873911446951680. Its totient is φ = 256591112601600.
The previous prime is 513512245534241. The next prime is 513512245534331. The reversal of 513512245534245 is 542435542215315.
It is not a de Polignac number, because 513512245534245 - 22 = 513512245534241 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (513512245534241) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 68748630 + ... + 75851160.
It is an arithmetic number, because the mean of its divisors is an integer number (13654866358620).
Almost surely, 2513512245534245 is an apocalyptic number.
It is an amenable number.
513512245534245 is a deficient number, since it is larger than the sum of its proper divisors (360399201417435).
513512245534245 is a wasteful number, since it uses less digits than its factorization.
513512245534245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7103846.
The product of its digits is 14400000, while the sum is 51.
The spelling of 513512245534245 in words is "five hundred thirteen trillion, five hundred twelve billion, two hundred forty-five million, five hundred thirty-four thousand, two hundred forty-five".
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