Base | Representation |
---|---|
bin | 100101010111011111000… |
… | …0010111110110001001111 |
3 | 200011222001222101021220111 |
4 | 1022232332002332301033 |
5 | 1133120330114334101 |
6 | 14531143553100451 |
7 | 1040016540613462 |
oct | 112567602766117 |
9 | 20158058337814 |
10 | 5135674371151 |
11 | 1700033328725 |
12 | 6ab3b2b57727 |
13 | 2b33a473255c |
14 | 13a7d46d92d9 |
15 | 8d8cd7ea251 |
hex | 4abbe0bec4f |
5135674371151 has 2 divisors, whose sum is σ = 5135674371152. Its totient is φ = 5135674371150.
The previous prime is 5135674371131. The next prime is 5135674371167. The reversal of 5135674371151 is 1511734765315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5135674371151 - 215 = 5135674338383 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5135674371095 and 5135674371104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5135674371131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2567837185575 + 2567837185576.
It is an arithmetic number, because the mean of its divisors is an integer number (2567837185576).
Almost surely, 25135674371151 is an apocalyptic number.
5135674371151 is a deficient number, since it is larger than the sum of its proper divisors (1).
5135674371151 is an equidigital number, since it uses as much as digits as its factorization.
5135674371151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1323000, while the sum is 49.
The spelling of 5135674371151 in words is "five trillion, one hundred thirty-five billion, six hundred seventy-four million, three hundred seventy-one thousand, one hundred fifty-one".
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