Base | Representation |
---|---|
bin | 100101010111100000100… |
… | …1000011011100000011111 |
3 | 200011222012120202222101111 |
4 | 1022233001020123200133 |
5 | 1133120431342144411 |
6 | 14531153042322451 |
7 | 1040021036561503 |
oct | 112570110334037 |
9 | 20158176688344 |
10 | 5135726131231 |
11 | 170005a570853 |
12 | 6ab408359427 |
13 | 2b33b2385b17 |
14 | 13a7db530303 |
15 | 8d8d3121721 |
hex | 4abc121b81f |
5135726131231 has 2 divisors, whose sum is σ = 5135726131232. Its totient is φ = 5135726131230.
The previous prime is 5135726131219. The next prime is 5135726131307. The reversal of 5135726131231 is 1321316275315.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5135726131231 - 217 = 5135726000159 is a prime.
It is a super-2 number, since 2×51357261312312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5135726131331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2567863065615 + 2567863065616.
It is an arithmetic number, because the mean of its divisors is an integer number (2567863065616).
Almost surely, 25135726131231 is an apocalyptic number.
5135726131231 is a deficient number, since it is larger than the sum of its proper divisors (1).
5135726131231 is an equidigital number, since it uses as much as digits as its factorization.
5135726131231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 113400, while the sum is 40.
The spelling of 5135726131231 in words is "five trillion, one hundred thirty-five billion, seven hundred twenty-six million, one hundred thirty-one thousand, two hundred thirty-one".
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