Base | Representation |
---|---|
bin | 1001100100010100… |
… | …10100101101110111 |
3 | 111020222021222112111 |
4 | 10302022110231313 |
5 | 41004423100031 |
6 | 2205405431451 |
7 | 241200551632 |
oct | 46212245567 |
9 | 14228258474 |
10 | 5136534391 |
11 | 21a649234a |
12 | bb426b587 |
13 | 63b224681 |
14 | 36a282c19 |
15 | 200e261b1 |
hex | 132294b77 |
5136534391 has 2 divisors, whose sum is σ = 5136534392. Its totient is φ = 5136534390.
The previous prime is 5136534331. The next prime is 5136534413. The reversal of 5136534391 is 1934356315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5136534391 - 29 = 5136533879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5136534301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2568267195 + 2568267196.
It is an arithmetic number, because the mean of its divisors is an integer number (2568267196).
Almost surely, 25136534391 is an apocalyptic number.
5136534391 is a deficient number, since it is larger than the sum of its proper divisors (1).
5136534391 is an equidigital number, since it uses as much as digits as its factorization.
5136534391 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 145800, while the sum is 40.
The square root of 5136534391 is about 71669.6197213296. The cubic root of 5136534391 is about 1725.4010847512.
The spelling of 5136534391 in words is "five billion, one hundred thirty-six million, five hundred thirty-four thousand, three hundred ninety-one".
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