Base | Representation |
---|---|
bin | 10111010110111100111001… |
… | …00111011000101110010111 |
3 | 20201212112222201100012011101 |
4 | 23223132130213120232113 |
5 | 23213040324203312242 |
6 | 301125140222050531 |
7 | 13551036604312456 |
oct | 1353363447305627 |
9 | 221775881305141 |
10 | 51366141463447 |
11 | 1540429281a768 |
12 | 5917128a19a47 |
13 | 2287a63743825 |
14 | c981c515ab9d |
15 | 5e12405659b7 |
hex | 2eb79c9d8b97 |
51366141463447 has 2 divisors, whose sum is σ = 51366141463448. Its totient is φ = 51366141463446.
The previous prime is 51366141463421. The next prime is 51366141463489. The reversal of 51366141463447 is 74436414166315.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51366141463447 - 27 = 51366141463319 is a prime.
It is a super-2 number, since 2×513661414634472 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51366141463547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25683070731723 + 25683070731724.
It is an arithmetic number, because the mean of its divisors is an integer number (25683070731724).
Almost surely, 251366141463447 is an apocalyptic number.
51366141463447 is a deficient number, since it is larger than the sum of its proper divisors (1).
51366141463447 is an equidigital number, since it uses as much as digits as its factorization.
51366141463447 is an evil number, because the sum of its binary digits is even.
The product of its digits is 17418240, while the sum is 55.
The spelling of 51366141463447 in words is "fifty-one trillion, three hundred sixty-six billion, one hundred forty-one million, four hundred sixty-three thousand, four hundred forty-seven".
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