Base | Representation |
---|---|
bin | 10111010111010011110111… |
… | …01100110010101010010111 |
3 | 20201220201211012102202221121 |
4 | 23223221323230302222113 |
5 | 23213241103334243132 |
6 | 301134540054024411 |
7 | 13551654325266625 |
oct | 1353517354625227 |
9 | 221821735382847 |
10 | 51378474134167 |
11 | 1540954123a814 |
12 | 59195ab048107 |
13 | 2288c7a7a491b |
14 | c98a35014515 |
15 | 5e17130ea497 |
hex | 2eba7bb32a97 |
51378474134167 has 2 divisors, whose sum is σ = 51378474134168. Its totient is φ = 51378474134166.
The previous prime is 51378474134089. The next prime is 51378474134209. The reversal of 51378474134167 is 76143147487315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51378474134167 - 215 = 51378474101399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51378474134467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25689237067083 + 25689237067084.
It is an arithmetic number, because the mean of its divisors is an integer number (25689237067084).
Almost surely, 251378474134167 is an apocalyptic number.
51378474134167 is a deficient number, since it is larger than the sum of its proper divisors (1).
51378474134167 is an equidigital number, since it uses as much as digits as its factorization.
51378474134167 is an evil number, because the sum of its binary digits is even.
The product of its digits is 47416320, while the sum is 61.
The spelling of 51378474134167 in words is "fifty-one trillion, three hundred seventy-eight billion, four hundred seventy-four million, one hundred thirty-four thousand, one hundred sixty-seven".
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