Base | Representation |
---|---|
bin | 1001100100100110… |
… | …00010101110111111 |
3 | 111021010121002211211 |
4 | 10302103002232333 |
5 | 41011014220111 |
6 | 2205530425251 |
7 | 241226151412 |
oct | 46223025677 |
9 | 14233532754 |
10 | 5138820031 |
11 | 21a7803604 |
12 | bb4b92227 |
13 | 63b844b17 |
14 | 36a6b9b79 |
15 | 201228521 |
hex | 1324c2bbf |
5138820031 has 2 divisors, whose sum is σ = 5138820032. Its totient is φ = 5138820030.
The previous prime is 5138820017. The next prime is 5138820041. The reversal of 5138820031 is 1300288315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5138820031 - 29 = 5138819519 is a prime.
It is a super-2 number, since 2×51388200312 = 52814942622013681922, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5138819975 and 5138820002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5138820041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2569410015 + 2569410016.
It is an arithmetic number, because the mean of its divisors is an integer number (2569410016).
Almost surely, 25138820031 is an apocalyptic number.
5138820031 is a deficient number, since it is larger than the sum of its proper divisors (1).
5138820031 is an equidigital number, since it uses as much as digits as its factorization.
5138820031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 31.
The square root of 5138820031 is about 71685.5636163935. The cubic root of 5138820031 is about 1725.6569681047.
The spelling of 5138820031 in words is "five billion, one hundred thirty-eight million, eight hundred twenty thousand, thirty-one".
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