Base | Representation |
---|---|
bin | 100101011000111101000… |
… | …1001110100100101100011 |
3 | 200012021012220210010102122 |
4 | 1022301322021310211203 |
5 | 1133143311022443214 |
6 | 14532425051134455 |
7 | 1040161001452136 |
oct | 112617211644543 |
9 | 20167186703378 |
10 | 5138830281059 |
11 | 17014027a7532 |
12 | 6abb33a4442b |
13 | 2b3788504977 |
14 | 13aa138c821d |
15 | 8da158d988e |
hex | 4ac7a274963 |
5138830281059 has 2 divisors, whose sum is σ = 5138830281060. Its totient is φ = 5138830281058.
The previous prime is 5138830281047. The next prime is 5138830281083. The reversal of 5138830281059 is 9501820388315.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5138830281059 - 240 = 4039318653283 is a prime.
It is a super-2 number, since 2×51388302810592 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5138830281059.
It is not a weakly prime, because it can be changed into another prime (5138830289059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2569415140529 + 2569415140530.
It is an arithmetic number, because the mean of its divisors is an integer number (2569415140530).
Almost surely, 25138830281059 is an apocalyptic number.
5138830281059 is a deficient number, since it is larger than the sum of its proper divisors (1).
5138830281059 is an equidigital number, since it uses as much as digits as its factorization.
5138830281059 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2073600, while the sum is 53.
The spelling of 5138830281059 in words is "five trillion, one hundred thirty-eight billion, eight hundred thirty million, two hundred eighty-one thousand, fifty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.122 sec. • engine limits •