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514000212053 is a prime number
BaseRepresentation
bin1110111101011001100…
…11001101000001010101
31211010201120002011200212
413132230303031001111
531410133023241203
61032043424215205
752064255500166
oct7365463150125
91733646064625
10514000212053
11188a937a0a89
128374976a505
1339615802313
141ac4075376d
15d584ca91d8
hex77acccd055

514000212053 has 2 divisors, whose sum is σ = 514000212054. Its totient is φ = 514000212052.

The previous prime is 514000212001. The next prime is 514000212109. The reversal of 514000212053 is 350212000415.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 371779209169 + 142221002884 = 609737^2 + 377122^2 .

It is a cyclic number.

It is not a de Polignac number, because 514000212053 - 220 = 513999163477 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (514000212853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257000106026 + 257000106027.

It is an arithmetic number, because the mean of its divisors is an integer number (257000106027).

Almost surely, 2514000212053 is an apocalyptic number.

It is an amenable number.

514000212053 is a deficient number, since it is larger than the sum of its proper divisors (1).

514000212053 is an equidigital number, since it uses as much as digits as its factorization.

514000212053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 23.

Adding to 514000212053 its reverse (350212000415), we get a palindrome (864212212468).

The spelling of 514000212053 in words is "five hundred fourteen billion, two hundred twelve thousand, fifty-three".