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5140101440113 is a prime number
BaseRepresentation
bin100101011001100010111…
…1010111010001001110001
3200012101111111200200211121
41022303011322322021301
51133203411432040423
614533155140342241
71040234335232203
oct112630572721161
920171444620747
105140101440113
1117019a5296102
126b02296a4981
132b392b9823a3
1413aad465c773
158da8c2ce45d
hex4acc5eba271

5140101440113 has 2 divisors, whose sum is σ = 5140101440114. Its totient is φ = 5140101440112.

The previous prime is 5140101440081. The next prime is 5140101440143. The reversal of 5140101440113 is 3110441010415.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4177805185024 + 962296255089 = 2043968^2 + 980967^2 .

It is a cyclic number.

It is not a de Polignac number, because 5140101440113 - 25 = 5140101440081 is a prime.

It is not a weakly prime, because it can be changed into another prime (5140101440143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2570050720056 + 2570050720057.

It is an arithmetic number, because the mean of its divisors is an integer number (2570050720057).

Almost surely, 25140101440113 is an apocalyptic number.

It is an amenable number.

5140101440113 is a deficient number, since it is larger than the sum of its proper divisors (1).

5140101440113 is an equidigital number, since it uses as much as digits as its factorization.

5140101440113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 25.

Adding to 5140101440113 its reverse (3110441010415), we get a palindrome (8250542450528).

The spelling of 5140101440113 in words is "five trillion, one hundred forty billion, one hundred one million, four hundred forty thousand, one hundred thirteen".