Base | Representation |
---|---|
bin | 111010011100001010100101… |
… | …0101100111000101011101011 |
3 | 2111102002011111001110202122002 |
4 | 1310320111022230320223223 |
5 | 1014334100430002233001 |
6 | 5021140424353121215 |
7 | 213163324533221024 |
oct | 16470251254705353 |
9 | 2442064431422562 |
10 | 514044414102251 |
11 | 13987701471788a |
12 | 497a130225920b |
13 | 190aa246029cc6 |
14 | 90d1c4d401c4b |
15 | 3e6671caa546b |
hex | 1d3854ab38aeb |
514044414102251 has 2 divisors, whose sum is σ = 514044414102252. Its totient is φ = 514044414102250.
The previous prime is 514044414102143. The next prime is 514044414102311. The reversal of 514044414102251 is 152201414440415.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-514044414102251 is a prime.
It is not a weakly prime, because it can be changed into another prime (514044414102451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257022207051125 + 257022207051126.
It is an arithmetic number, because the mean of its divisors is an integer number (257022207051126).
Almost surely, 2514044414102251 is an apocalyptic number.
514044414102251 is a deficient number, since it is larger than the sum of its proper divisors (1).
514044414102251 is an equidigital number, since it uses as much as digits as its factorization.
514044414102251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 102400, while the sum is 38.
Adding to 514044414102251 its reverse (152201414440415), we get a palindrome (666245828542666).
The spelling of 514044414102251 in words is "five hundred fourteen trillion, forty-four billion, four hundred fourteen million, one hundred two thousand, two hundred fifty-one".
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