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51405020231 is a prime number
BaseRepresentation
bin101111110111111110…
…100101110001000111
311220200111121121001012
4233313332211301013
51320234141121411
635340511552435
73466602314435
oct576776456107
9156614547035
1051405020231
111a8898805a4
129b6752b71b
134b02b88546
1426b918bd55
15150cdcc18b
hexbf7fa5c47

51405020231 has 2 divisors, whose sum is σ = 51405020232. Its totient is φ = 51405020230.

The previous prime is 51405020209. The next prime is 51405020243. The reversal of 51405020231 is 13202050415.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 51405020231 - 210 = 51405019207 is a prime.

It is a super-2 number, since 2×514050202312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51405020197 and 51405020206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51405020131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25702510115 + 25702510116.

It is an arithmetic number, because the mean of its divisors is an integer number (25702510116).

Almost surely, 251405020231 is an apocalyptic number.

51405020231 is a deficient number, since it is larger than the sum of its proper divisors (1).

51405020231 is an equidigital number, since it uses as much as digits as its factorization.

51405020231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 23.

Adding to 51405020231 its reverse (13202050415), we get a palindrome (64607070646).

The spelling of 51405020231 in words is "fifty-one billion, four hundred five million, twenty thousand, two hundred thirty-one".