Base | Representation |
---|---|
bin | 10111011000010010011000… |
… | …11100101110000000100011 |
3 | 20202000221110112122211202012 |
4 | 23230021030130232000203 |
5 | 23214313330012130034 |
6 | 301202210551143135 |
7 | 13554253210120403 |
oct | 1354111434560043 |
9 | 222027415584665 |
10 | 51412041130019 |
11 | 154217a69aa5a9 |
12 | 5923bb8674aab |
13 | 228c199b6264b |
14 | c9a4db09a803 |
15 | 5e2529e66cce |
hex | 2ec24c72e023 |
51412041130019 has 2 divisors, whose sum is σ = 51412041130020. Its totient is φ = 51412041130018.
The previous prime is 51412041129989. The next prime is 51412041130057. The reversal of 51412041130019 is 91003114021415.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51412041130019 - 212 = 51412041125923 is a prime.
It is a super-2 number, since 2×514120411300192 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51412041330019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25706020565009 + 25706020565010.
It is an arithmetic number, because the mean of its divisors is an integer number (25706020565010).
Almost surely, 251412041130019 is an apocalyptic number.
51412041130019 is a deficient number, since it is larger than the sum of its proper divisors (1).
51412041130019 is an equidigital number, since it uses as much as digits as its factorization.
51412041130019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 32.
The spelling of 51412041130019 in words is "fifty-one trillion, four hundred twelve billion, forty-one million, one hundred thirty thousand, nineteen".
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