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51413647387663 = 114673967944333
BaseRepresentation
bin10111011000010101011000…
…01100000110110000001111
320202001002121111010012000001
423230022230030012300033
523214330122212401123
6301203034210545131
713554341053102321
oct1354125414066017
9222032544105001
1051413647387663
1115422450665760
1259243865981a7
13228c394879762
14c9a61053d611
155e25c0ea00ad
hex2ec2ac306c0f

51413647387663 has 4 divisors (see below), whose sum is σ = 56087615332008. Its totient is φ = 46739679443320.

The previous prime is 51413647387651. The next prime is 51413647387681. The reversal of 51413647387663 is 36678374631415.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51413647387663 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51413647387595 and 51413647387604.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51413647387693) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2336983972156 + ... + 2336983972177.

It is an arithmetic number, because the mean of its divisors is an integer number (14021903833002).

Almost surely, 251413647387663 is an apocalyptic number.

51413647387663 is a deficient number, since it is larger than the sum of its proper divisors (4673967944345).

51413647387663 is a wasteful number, since it uses less digits than its factorization.

51413647387663 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4673967944344.

The product of its digits is 182891520, while the sum is 64.

The spelling of 51413647387663 in words is "fifty-one trillion, four hundred thirteen billion, six hundred forty-seven million, three hundred eighty-seven thousand, six hundred sixty-three".

Divisors: 1 11 4673967944333 51413647387663