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514146136241 is a prime number
BaseRepresentation
bin1110111101101010111…
…11110111000010110001
31211011002201122220001102
413132311133313002301
531410432402324431
61032110120014145
752101010023143
oct7366537670261
91734081586042
10514146136241
111890590a9a91
128378a601355
1339639b04caa
141ac55c9ac93
15d5929d0dcb
hex77b57f70b1

514146136241 has 2 divisors, whose sum is σ = 514146136242. Its totient is φ = 514146136240.

The previous prime is 514146136211. The next prime is 514146136247. The reversal of 514146136241 is 142631641415.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 503916836641 + 10229299600 = 709871^2 + 101140^2 .

It is a cyclic number.

It is not a de Polignac number, because 514146136241 - 238 = 239268229297 is a prime.

It is a super-2 number, since 2×5141461362412 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 514146136195 and 514146136204.

It is not a weakly prime, because it can be changed into another prime (514146136247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257073068120 + 257073068121.

It is an arithmetic number, because the mean of its divisors is an integer number (257073068121).

Almost surely, 2514146136241 is an apocalyptic number.

It is an amenable number.

514146136241 is a deficient number, since it is larger than the sum of its proper divisors (1).

514146136241 is an equidigital number, since it uses as much as digits as its factorization.

514146136241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 69120, while the sum is 38.

Adding to 514146136241 its reverse (142631641415), we get a palindrome (656777777656).

The spelling of 514146136241 in words is "five hundred fourteen billion, one hundred forty-six million, one hundred thirty-six thousand, two hundred forty-one".