Base | Representation |
---|---|
bin | 101111111000101010… |
… | …101111010110111101 |
3 | 11220201022101121001212 |
4 | 233320222233112331 |
5 | 1320300122000403 |
6 | 35342004014205 |
7 | 3500102556662 |
oct | 577052572675 |
9 | 156638347055 |
10 | 51416593853 |
11 | 1a895365a79 |
12 | 9b6b391365 |
13 | 4b053ab441 |
14 | 26ba921a69 |
15 | 150de164d8 |
hex | bf8aaf5bd |
51416593853 has 2 divisors, whose sum is σ = 51416593854. Its totient is φ = 51416593852.
The previous prime is 51416593847. The next prime is 51416593871. The reversal of 51416593853 is 35839561415.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 51219837124 + 196756729 = 226318^2 + 14027^2 .
It is a cyclic number.
It is not a de Polignac number, because 51416593853 - 232 = 47121626557 is a prime.
It is a super-2 number, since 2×514165938532 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51416593843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25708296926 + 25708296927.
It is an arithmetic number, because the mean of its divisors is an integer number (25708296927).
Almost surely, 251416593853 is an apocalyptic number.
It is an amenable number.
51416593853 is a deficient number, since it is larger than the sum of its proper divisors (1).
51416593853 is an equidigital number, since it uses as much as digits as its factorization.
51416593853 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1944000, while the sum is 50.
The spelling of 51416593853 in words is "fifty-one billion, four hundred sixteen million, five hundred ninety-three thousand, eight hundred fifty-three".
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