Base | Representation |
---|---|
bin | 101111111000111011… |
… | …001000010000000001 |
3 | 11220201121110212102121 |
4 | 233320323020100001 |
5 | 1320302221440423 |
6 | 35342240044241 |
7 | 3500154232345 |
oct | 577073102001 |
9 | 156647425377 |
10 | 51420890113 |
11 | 1a89782a8aa |
12 | 9b70903681 |
13 | 4b06253ac8 |
14 | 26bb31d625 |
15 | 150e4b445d |
hex | bf8ec8401 |
51420890113 has 2 divisors, whose sum is σ = 51420890114. Its totient is φ = 51420890112.
The previous prime is 51420890107. The next prime is 51420890117. The reversal of 51420890113 is 31109802415.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 47841500529 + 3579389584 = 218727^2 + 59828^2 .
It is a cyclic number.
It is not a de Polignac number, because 51420890113 - 213 = 51420881921 is a prime.
It is not a weakly prime, because it can be changed into another prime (51420890117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25710445056 + 25710445057.
It is an arithmetic number, because the mean of its divisors is an integer number (25710445057).
Almost surely, 251420890113 is an apocalyptic number.
It is an amenable number.
51420890113 is a deficient number, since it is larger than the sum of its proper divisors (1).
51420890113 is an equidigital number, since it uses as much as digits as its factorization.
51420890113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 34.
The spelling of 51420890113 in words is "fifty-one billion, four hundred twenty million, eight hundred ninety thousand, one hundred thirteen".
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