Base | Representation |
---|---|
bin | 100101011010011111110… |
… | …0011000110100110101011 |
3 | 200012120202201101220012212 |
4 | 1022310333203012212223 |
5 | 1133222101324120021 |
6 | 14534133433155335 |
7 | 1040336033665553 |
oct | 112647743064653 |
9 | 20176681356185 |
10 | 5142142020011 |
11 | 1702852129a77 |
12 | 6b06b8b5bb4b |
13 | 2b3b95667209 |
14 | 13ac4967c163 |
15 | 8db5b50a85b |
hex | 4ad3f8c69ab |
5142142020011 has 2 divisors, whose sum is σ = 5142142020012. Its totient is φ = 5142142020010.
The previous prime is 5142142019947. The next prime is 5142142020013. The reversal of 5142142020011 is 1100202412415.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5142142020011 - 26 = 5142142019947 is a prime.
Together with 5142142020013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (5142142020013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2571071010005 + 2571071010006.
It is an arithmetic number, because the mean of its divisors is an integer number (2571071010006).
Almost surely, 25142142020011 is an apocalyptic number.
5142142020011 is a deficient number, since it is larger than the sum of its proper divisors (1).
5142142020011 is an equidigital number, since it uses as much as digits as its factorization.
5142142020011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 640, while the sum is 23.
Adding to 5142142020011 its reverse (1100202412415), we get a palindrome (6242344432426).
The spelling of 5142142020011 in words is "five trillion, one hundred forty-two billion, one hundred forty-two million, twenty thousand, eleven".
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