Base | Representation |
---|---|
bin | 101111111001101010… |
… | …010011000011010001 |
3 | 11220202110202002000212 |
4 | 233321222103003101 |
5 | 1320313403130441 |
6 | 35343401053505 |
7 | 3500364312053 |
oct | 577152230321 |
9 | 156673662025 |
10 | 51433255121 |
11 | 1a8a3805916 |
12 | 9b74a87295 |
13 | 4b08992c91 |
14 | 26bcc1b8d3 |
15 | 1510607eeb |
hex | bf9a930d1 |
51433255121 has 2 divisors, whose sum is σ = 51433255122. Its totient is φ = 51433255120.
The previous prime is 51433255099. The next prime is 51433255129. The reversal of 51433255121 is 12155233415.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 33375270721 + 18057984400 = 182689^2 + 134380^2 .
It is a cyclic number.
It is not a de Polignac number, because 51433255121 - 230 = 50359513297 is a prime.
It is not a weakly prime, because it can be changed into another prime (51433255129) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25716627560 + 25716627561.
It is an arithmetic number, because the mean of its divisors is an integer number (25716627561).
Almost surely, 251433255121 is an apocalyptic number.
It is an amenable number.
51433255121 is a deficient number, since it is larger than the sum of its proper divisors (1).
51433255121 is an equidigital number, since it uses as much as digits as its factorization.
51433255121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 18000, while the sum is 32.
Adding to 51433255121 its reverse (12155233415), we get a palindrome (63588488536).
The spelling of 51433255121 in words is "fifty-one billion, four hundred thirty-three million, two hundred fifty-five thousand, one hundred twenty-one".
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