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51434203202101 is a prime number
BaseRepresentation
bin10111011000111011101010…
…11010010100001000110101
320202010001200001111202022201
423230131311122110020311
523220144222004431401
6301220314033224501
713555666334455426
oct1354356532241065
9222101601452281
1051434203202101
1115430139903355
125928362702131
1322912bc44c275
14c9b60058964d
155e2dc590bb01
hex2ec775694235

51434203202101 has 2 divisors, whose sum is σ = 51434203202102. Its totient is φ = 51434203202100.

The previous prime is 51434203202087. The next prime is 51434203202117. The reversal of 51434203202101 is 10120230243415.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 41333661123876 + 10100542078225 = 6429126^2 + 3178135^2 .

It is a cyclic number.

It is not a de Polignac number, because 51434203202101 - 215 = 51434203169333 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 51434203202101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51434203202401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25717101601050 + 25717101601051.

It is an arithmetic number, because the mean of its divisors is an integer number (25717101601051).

Almost surely, 251434203202101 is an apocalyptic number.

It is an amenable number.

51434203202101 is a deficient number, since it is larger than the sum of its proper divisors (1).

51434203202101 is an equidigital number, since it uses as much as digits as its factorization.

51434203202101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 51434203202101 its reverse (10120230243415), we get a palindrome (61554433445516).

The spelling of 51434203202101 in words is "fifty-one trillion, four hundred thirty-four billion, two hundred three million, two hundred two thousand, one hundred one".