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514343201540317 is a prime number
BaseRepresentation
bin111010011110010101101101…
…1110100100000100011011101
32111110010201201001202021002221
41310330223123310200203131
51014403444334043242232
65021530001012545341
7213224033005435402
oct16474533364404335
92443121631667087
10514343201540317
111399817aa408386
124982b1a9622251
13190cc481886736
1491024b54a42a9
153e6e3a8a96897
hex1d3cadbd208dd

514343201540317 has 2 divisors, whose sum is σ = 514343201540318. Its totient is φ = 514343201540316.

The previous prime is 514343201540281. The next prime is 514343201540341. The reversal of 514343201540317 is 713045102343415.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 513150888231556 + 1192313308761 = 22652834^2 + 1091931^2 .

It is a cyclic number.

It is not a de Polignac number, because 514343201540317 - 215 = 514343201507549 is a prime.

It is a super-2 number, since 2×5143432015403172 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (514343201543317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257171600770158 + 257171600770159.

It is an arithmetic number, because the mean of its divisors is an integer number (257171600770159).

Almost surely, 2514343201540317 is an apocalyptic number.

It is an amenable number.

514343201540317 is a deficient number, since it is larger than the sum of its proper divisors (1).

514343201540317 is an equidigital number, since it uses as much as digits as its factorization.

514343201540317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 604800, while the sum is 43.

The spelling of 514343201540317 in words is "five hundred fourteen trillion, three hundred forty-three billion, two hundred one million, five hundred forty thousand, three hundred seventeen".