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5143534125299 is a prime number
BaseRepresentation
bin100101011011001001010…
…0001100100000011110011
3200012201100201220011122222
41022312102201210003303
51133232424214002144
614534523522551255
71040415366460553
oct112662241440363
920181321804588
105143534125299
1117033a6a16309
126b0a2720852b
132b4057bb045b
1413ad3c4d7163
158dbdd8412ee
hex4ad928640f3

5143534125299 has 2 divisors, whose sum is σ = 5143534125300. Its totient is φ = 5143534125298.

The previous prime is 5143534125241. The next prime is 5143534125307. The reversal of 5143534125299 is 9925214353415.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5143534125299 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5143534125299.

It is not a weakly prime, because it can be changed into another prime (5143534127299) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2571767062649 + 2571767062650.

It is an arithmetic number, because the mean of its divisors is an integer number (2571767062650).

Almost surely, 25143534125299 is an apocalyptic number.

5143534125299 is a deficient number, since it is larger than the sum of its proper divisors (1).

5143534125299 is an equidigital number, since it uses as much as digits as its factorization.

5143534125299 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5832000, while the sum is 53.

The spelling of 5143534125299 in words is "five trillion, one hundred forty-three billion, five hundred thirty-four million, one hundred twenty-five thousand, two hundred ninety-nine".