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5143720184 = 2323276710103
BaseRepresentation
bin1001100101001011…
…01111000011111000
3111021110211001120222
410302211233003320
541013243021214
62210223435212
7241315620521
oct46245570370
914243731528
105143720184
1121aa550119
12bb6755b08
1363c86c315
1436b1d3848
1520189538e
hex13296f0f8

5143720184 has 32 divisors (see below), whose sum is σ = 10068433920. Its totient is φ = 2458907616.

The previous prime is 5143720177. The next prime is 5143720189. The reversal of 5143720184 is 4810273415.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5143720189) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 504077 + ... + 514179.

It is an arithmetic number, because the mean of its divisors is an integer number (314638560).

Almost surely, 25143720184 is an apocalyptic number.

It is an amenable number.

5143720184 is a deficient number, since it is larger than the sum of its proper divisors (4924713736).

5143720184 is a wasteful number, since it uses less digits than its factorization.

5143720184 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12899 (or 12895 counting only the distinct ones).

The product of its (nonzero) digits is 26880, while the sum is 35.

The square root of 5143720184 is about 71719.7335745191. The cubic root of 5143720184 is about 1726.2052974092.

Adding to 5143720184 its reverse (4810273415), we get a palindrome (9953993599).

The spelling of 5143720184 in words is "five billion, one hundred forty-three million, seven hundred twenty thousand, one hundred eighty-four".

Divisors: 1 2 4 8 23 46 92 184 2767 5534 10103 11068 20206 22136 40412 63641 80824 127282 232369 254564 464738 509128 929476 1858952 27955001 55910002 111820004 223640008 642965023 1285930046 2571860092 5143720184