Base | Representation |
---|---|
bin | 100101011011010110101… |
… | …1000110100010011100101 |
3 | 200012202112010221200222022 |
4 | 1022312231120310103211 |
5 | 1133234340103124011 |
6 | 14535040342512525 |
7 | 1040432511341624 |
oct | 112665530642345 |
9 | 20182463850868 |
10 | 5143984817381 |
11 | 1703608364a03 |
12 | 6b0b32135745 |
13 | 2b40ca390167 |
14 | 13ad822d56bb |
15 | 8dc181b98db |
hex | 4adad6344e5 |
5143984817381 has 2 divisors, whose sum is σ = 5143984817382. Its totient is φ = 5143984817380.
The previous prime is 5143984817371. The next prime is 5143984817459. The reversal of 5143984817381 is 1837184893415.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3361850596225 + 1782134221156 = 1833535^2 + 1334966^2 .
It is a cyclic number.
It is not a de Polignac number, because 5143984817381 - 242 = 745938306277 is a prime.
It is a super-2 number, since 2×51439848173812 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5143984817371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2571992408690 + 2571992408691.
It is an arithmetic number, because the mean of its divisors is an integer number (2571992408691).
Almost surely, 25143984817381 is an apocalyptic number.
It is an amenable number.
5143984817381 is a deficient number, since it is larger than the sum of its proper divisors (1).
5143984817381 is an equidigital number, since it uses as much as digits as its factorization.
5143984817381 is an evil number, because the sum of its binary digits is even.
The product of its digits is 23224320, while the sum is 62.
The spelling of 5143984817381 in words is "five trillion, one hundred forty-three billion, nine hundred eighty-four million, eight hundred seventeen thousand, three hundred eighty-one".
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