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51450533734553 is a prime number
BaseRepresentation
bin10111011001011010000101…
…10010010110100010011001
320202011121211011021202101222
423230231002302112202121
523220431143114001203
6301232014321221425
713560115121632262
oct1354550262264231
9222147734252358
1051450533734553
1115437059a87068
12592b55b791875
1322929c2833715
14c9c30d39b969
155e352e443038
hex2ecb42c96899

51450533734553 has 2 divisors, whose sum is σ = 51450533734554. Its totient is φ = 51450533734552.

The previous prime is 51450533734519. The next prime is 51450533734571. The reversal of 51450533734553 is 35543733505415.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39940276508224 + 11510257226329 = 6319832^2 + 3392677^2 .

It is a cyclic number.

It is not a de Polignac number, because 51450533734553 - 236 = 51381814257817 is a prime.

It is a super-2 number, since 2×514505337345532 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51450533734495 and 51450533734504.

It is not a weakly prime, because it can be changed into another prime (51450533794553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25725266867276 + 25725266867277.

It is an arithmetic number, because the mean of its divisors is an integer number (25725266867277).

Almost surely, 251450533734553 is an apocalyptic number.

It is an amenable number.

51450533734553 is a deficient number, since it is larger than the sum of its proper divisors (1).

51450533734553 is an equidigital number, since it uses as much as digits as its factorization.

51450533734553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28350000, while the sum is 53.

The spelling of 51450533734553 in words is "fifty-one trillion, four hundred fifty billion, five hundred thirty-three million, seven hundred thirty-four thousand, five hundred fifty-three".