Base | Representation |
---|---|
bin | 100101011011111001001… |
… | …1101011010111110111011 |
3 | 200012212111220111121121111 |
4 | 1022313302131122332323 |
5 | 1133244223233333113 |
6 | 14535351340421151 |
7 | 1040503312310215 |
oct | 112676235327673 |
9 | 20185456447544 |
10 | 5145143652283 |
11 | 17040525047a8 |
12 | 6b11b62477b7 |
13 | 2b42534a069b |
14 | 13b05218b5b5 |
15 | 8dc84cc313d |
hex | 4adf275afbb |
5145143652283 has 2 divisors, whose sum is σ = 5145143652284. Its totient is φ = 5145143652282.
The previous prime is 5145143652281. The next prime is 5145143652323. The reversal of 5145143652283 is 3822563415415.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5145143652283 - 21 = 5145143652281 is a prime.
It is a super-2 number, since 2×51451436522832 (a number of 26 digits) contains 22 as substring.
Together with 5145143652281, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5145143652281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2572571826141 + 2572571826142.
It is an arithmetic number, because the mean of its divisors is an integer number (2572571826142).
Almost surely, 25145143652283 is an apocalyptic number.
5145143652283 is a deficient number, since it is larger than the sum of its proper divisors (1).
5145143652283 is an equidigital number, since it uses as much as digits as its factorization.
5145143652283 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3456000, while the sum is 49.
The spelling of 5145143652283 in words is "five trillion, one hundred forty-five billion, one hundred forty-three million, six hundred fifty-two thousand, two hundred eighty-three".
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