Base | Representation |
---|---|
bin | 101111111010110010… |
… | …010101101001001111 |
3 | 11220210210021112100221 |
4 | 233322302111221033 |
5 | 1320333221440421 |
6 | 35345313532211 |
7 | 3501013655251 |
oct | 577262255117 |
9 | 156723245327 |
10 | 51452140111 |
11 | 1a903434449 |
12 | 9b7b274067 |
13 | 4b0c875a28 |
14 | 26c1535cd1 |
15 | 15120d8841 |
hex | bfac95a4f |
51452140111 has 4 divisors (see below), whose sum is σ = 51554431152. Its totient is φ = 51349849072.
The previous prime is 51452140099. The next prime is 51452140219. The reversal of 51452140111 is 11104125415.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11104125415 = 5 ⋅2220825083.
It is a cyclic number.
It is not a de Polignac number, because 51452140111 - 25 = 51452140079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51452140511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51144766 + ... + 51145771.
It is an arithmetic number, because the mean of its divisors is an integer number (12888607788).
Almost surely, 251452140111 is an apocalyptic number.
51452140111 is a deficient number, since it is larger than the sum of its proper divisors (102291041).
51452140111 is a wasteful number, since it uses less digits than its factorization.
51452140111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102291040.
The product of its (nonzero) digits is 800, while the sum is 25.
Adding to 51452140111 its reverse (11104125415), we get a palindrome (62556265526).
The spelling of 51452140111 in words is "fifty-one billion, four hundred fifty-two million, one hundred forty thousand, one hundred eleven".
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