Base | Representation |
---|---|
bin | 1110111110011000110… |
… | …00001100110111001111 |
3 | 1211012002110222102012210 |
4 | 13133030120030313033 |
5 | 31412224140120211 |
6 | 1032212151401503 |
7 | 52113350606322 |
oct | 7371430146717 |
9 | 1735073872183 |
10 | 514530004431 |
11 | 189235856923 |
12 | 83877083293 |
13 | 3969b4b8a31 |
14 | 1ac90c627b9 |
15 | d5b65599a6 |
hex | 77cc60cdcf |
514530004431 has 32 divisors (see below), whose sum is σ = 729437529600. Its totient is φ = 322592534208.
The previous prime is 514530004427. The next prime is 514530004459. The reversal of 514530004431 is 134400035415.
It is not a de Polignac number, because 514530004431 - 22 = 514530004427 is a prime.
It is a super-2 number, since 2×5145300044312 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (514530004481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2727790 + ... + 2910308.
It is an arithmetic number, because the mean of its divisors is an integer number (22794922800).
Almost surely, 2514530004431 is an apocalyptic number.
514530004431 is a deficient number, since it is larger than the sum of its proper divisors (214907525169).
514530004431 is a wasteful number, since it uses less digits than its factorization.
514530004431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 182716 (or 182678 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 514530004431 its reverse (134400035415), we get a palindrome (648930039846).
The spelling of 514530004431 in words is "five hundred fourteen billion, five hundred thirty million, four thousand, four hundred thirty-one".
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