Base | Representation |
---|---|
bin | 100101011101001101010… |
… | …0110111111110000100101 |
3 | 200020010210111212102220002 |
4 | 1022322122212333300211 |
5 | 1133321012433001001 |
6 | 14540535314151045 |
7 | 1040633236152551 |
oct | 112723246776045 |
9 | 20203714772802 |
10 | 5147964734501 |
11 | 170526a981606 |
12 | 6b1862b82485 |
13 | 2b45b2a9c7c4 |
14 | 13b23cadc861 |
15 | 8dd9c7c446b |
hex | 4ae9a9bfc25 |
5147964734501 has 2 divisors, whose sum is σ = 5147964734502. Its totient is φ = 5147964734500.
The previous prime is 5147964734489. The next prime is 5147964734527. The reversal of 5147964734501 is 1054374697415.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3475148430625 + 1672816303876 = 1864175^2 + 1293374^2 .
It is a cyclic number.
It is not a de Polignac number, because 5147964734501 - 234 = 5130784865317 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5147964734531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2573982367250 + 2573982367251.
It is an arithmetic number, because the mean of its divisors is an integer number (2573982367251).
Almost surely, 25147964734501 is an apocalyptic number.
It is an amenable number.
5147964734501 is a deficient number, since it is larger than the sum of its proper divisors (1).
5147964734501 is an equidigital number, since it uses as much as digits as its factorization.
5147964734501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12700800, while the sum is 56.
The spelling of 5147964734501 in words is "five trillion, one hundred forty-seven billion, nine hundred sixty-four million, seven hundred thirty-four thousand, five hundred one".
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