Base | Representation |
---|---|
bin | 10111011010100101100101… |
… | …01110101111110100101111 |
3 | 20202022111102221220210020201 |
4 | 23231102302232233310233 |
5 | 23222112201013342112 |
6 | 301302400332054331 |
7 | 13563051426054541 |
oct | 1355226256576457 |
9 | 222274387823221 |
10 | 51491066543407 |
11 | 154522697702a7 |
12 | 59373920043a7 |
13 | 22967820b769a |
14 | ca0276621691 |
15 | 5e4602ac4257 |
hex | 2ed4b2bafd2f |
51491066543407 has 2 divisors, whose sum is σ = 51491066543408. Its totient is φ = 51491066543406.
The previous prime is 51491066543303. The next prime is 51491066543509. The reversal of 51491066543407 is 70434566019415.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51491066543407 - 231 = 51488919059759 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51491066547407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25745533271703 + 25745533271704.
It is an arithmetic number, because the mean of its divisors is an integer number (25745533271704).
Almost surely, 251491066543407 is an apocalyptic number.
51491066543407 is a deficient number, since it is larger than the sum of its proper divisors (1).
51491066543407 is an equidigital number, since it uses as much as digits as its factorization.
51491066543407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10886400, while the sum is 55.
The spelling of 51491066543407 in words is "fifty-one trillion, four hundred ninety-one billion, sixty-six million, five hundred forty-three thousand, four hundred seven".
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