Base | Representation |
---|---|
bin | 11110101100010… |
… | …000011110111011 |
3 | 1022212220120011022 |
4 | 132230100132323 |
5 | 2023304341311 |
6 | 123032253055 |
7 | 15521506424 |
oct | 3654203673 |
9 | 1285816138 |
10 | 514918331 |
11 | 244726844 |
12 | 12454118b |
13 | 828a9505 |
14 | 4c55a64b |
15 | 303135db |
hex | 1eb107bb |
514918331 has 2 divisors, whose sum is σ = 514918332. Its totient is φ = 514918330.
The previous prime is 514918309. The next prime is 514918333. The reversal of 514918331 is 133819415.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-514918331 is a prime.
It is a super-2 number, since 2×5149183312 = 530281775199651122, which contains 22 as substring.
Together with 514918333, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 514918291 and 514918300.
It is not a weakly prime, because it can be changed into another prime (514918333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257459165 + 257459166.
It is an arithmetic number, because the mean of its divisors is an integer number (257459166).
Almost surely, 2514918331 is an apocalyptic number.
514918331 is a deficient number, since it is larger than the sum of its proper divisors (1).
514918331 is an equidigital number, since it uses as much as digits as its factorization.
514918331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 12960, while the sum is 35.
The square root of 514918331 is about 22691.8119814174. The cubic root of 514918331 is about 801.5170853091.
The spelling of 514918331 in words is "five hundred fourteen million, nine hundred eighteen thousand, three hundred thirty-one".
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