Base | Representation |
---|---|
bin | 101111111101010010… |
… | …010100100100110101 |
3 | 11220220201012020101201 |
4 | 233331102110210311 |
5 | 1320424441010043 |
6 | 35353412452501 |
7 | 3502033306354 |
oct | 577522244465 |
9 | 156821166351 |
10 | 51494078773 |
11 | 1a9250795a5 |
12 | 9b9131a131 |
13 | 4b1846aac7 |
14 | 26c6d3199b |
15 | 1515b1ec4d |
hex | bfd494935 |
51494078773 has 2 divisors, whose sum is σ = 51494078774. Its totient is φ = 51494078772.
The previous prime is 51494078731. The next prime is 51494078777. The reversal of 51494078773 is 37787049415.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34550630884 + 16943447889 = 185878^2 + 130167^2 .
It is a cyclic number.
It is not a de Polignac number, because 51494078773 - 221 = 51491981621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51494078777) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25747039386 + 25747039387.
It is an arithmetic number, because the mean of its divisors is an integer number (25747039387).
Almost surely, 251494078773 is an apocalyptic number.
It is an amenable number.
51494078773 is a deficient number, since it is larger than the sum of its proper divisors (1).
51494078773 is an equidigital number, since it uses as much as digits as its factorization.
51494078773 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5927040, while the sum is 55.
The spelling of 51494078773 in words is "fifty-one billion, four hundred ninety-four million, seventy-eight thousand, seven hundred seventy-three".
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