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51514103351407 is a prime number
BaseRepresentation
bin10111011011010000011111…
…10101001100100001101111
320202101200220102201212220211
423231220033311030201233
523223001340424221112
6301321130302523251
713564525334516224
oct1355501765144157
9222350812655824
1051514103351407
11154610104100a4
12593b940b96527
1322989b3993518
14ca141dd7194b
155e50002550a7
hex2eda0fd4c86f

51514103351407 has 2 divisors, whose sum is σ = 51514103351408. Its totient is φ = 51514103351406.

The previous prime is 51514103351401. The next prime is 51514103351423. The reversal of 51514103351407 is 70415330141515.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51514103351407 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 51514103351407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51514103351401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25757051675703 + 25757051675704.

It is an arithmetic number, because the mean of its divisors is an integer number (25757051675704).

Almost surely, 251514103351407 is an apocalyptic number.

51514103351407 is a deficient number, since it is larger than the sum of its proper divisors (1).

51514103351407 is an equidigital number, since it uses as much as digits as its factorization.

51514103351407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126000, while the sum is 40.

The spelling of 51514103351407 in words is "fifty-one trillion, five hundred fourteen billion, one hundred three million, three hundred fifty-one thousand, four hundred seven".