Base | Representation |
---|---|
bin | 100101011111001001000… |
… | …0110101100011111100101 |
3 | 200020112111220010020001002 |
4 | 1022332102012230133211 |
5 | 1133403013424012144 |
6 | 14542503324043045 |
7 | 1041141156032246 |
oct | 112762206543745 |
9 | 20215456106032 |
10 | 5152117016549 |
11 | 1707000816568 |
12 | 6b2621693485 |
13 | 2b4ac510ba29 |
14 | 13b514372ccd |
15 | 8e0420ca14e |
hex | 4af921ac7e5 |
5152117016549 has 4 divisors (see below), whose sum is σ = 5152685754720. Its totient is φ = 5151548278380.
The previous prime is 5152117016531. The next prime is 5152117016551. The reversal of 5152117016549 is 9456107112515.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5152117016549 - 224 = 5152100239333 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5152117016149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 284355497 + ... + 284373614.
It is an arithmetic number, because the mean of its divisors is an integer number (1288171438680).
Almost surely, 25152117016549 is an apocalyptic number.
It is an amenable number.
5152117016549 is a deficient number, since it is larger than the sum of its proper divisors (568738171).
5152117016549 is an equidigital number, since it uses as much as digits as its factorization.
5152117016549 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 568738170.
The product of its (nonzero) digits is 378000, while the sum is 47.
The spelling of 5152117016549 in words is "five trillion, one hundred fifty-two billion, one hundred seventeen million, sixteen thousand, five hundred forty-nine".
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