Base | Representation |
---|---|
bin | 100101011111001001000… |
… | …0110101100011111100111 |
3 | 200020112111220010020001011 |
4 | 1022332102012230133213 |
5 | 1133403013424012201 |
6 | 14542503324043051 |
7 | 1041141156032251 |
oct | 112762206543747 |
9 | 20215456106034 |
10 | 5152117016551 |
11 | 170700081656a |
12 | 6b2621693487 |
13 | 2b4ac510ba2b |
14 | 13b514372cd1 |
15 | 8e0420ca151 |
hex | 4af921ac7e7 |
5152117016551 has 2 divisors, whose sum is σ = 5152117016552. Its totient is φ = 5152117016550.
The previous prime is 5152117016531. The next prime is 5152117016581. The reversal of 5152117016551 is 1556107112515.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5152117016551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5152117016531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2576058508275 + 2576058508276.
It is an arithmetic number, because the mean of its divisors is an integer number (2576058508276).
Almost surely, 25152117016551 is an apocalyptic number.
5152117016551 is a deficient number, since it is larger than the sum of its proper divisors (1).
5152117016551 is an equidigital number, since it uses as much as digits as its factorization.
5152117016551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52500, while the sum is 40.
The spelling of 5152117016551 in words is "five trillion, one hundred fifty-two billion, one hundred seventeen million, sixteen thousand, five hundred fifty-one".
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