Base | Representation |
---|---|
bin | 100101011111001010101… |
… | …0101011011010011101111 |
3 | 200020112122200002112102201 |
4 | 1022332111111123103233 |
5 | 1133403121312204332 |
6 | 14542512541402331 |
7 | 1041142414463455 |
oct | 112762525332357 |
9 | 20215580075381 |
10 | 5152171209967 |
11 | 1707029370911 |
12 | 6b26378693a7 |
13 | 2b4b03404a42 |
14 | 13b51b63c9d5 |
15 | 8e046c325e7 |
hex | 4af9555b4ef |
5152171209967 has 2 divisors, whose sum is σ = 5152171209968. Its totient is φ = 5152171209966.
The previous prime is 5152171209937. The next prime is 5152171210013. The reversal of 5152171209967 is 7699021712515.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5152171209967 - 211 = 5152171207919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5152171209937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2576085604983 + 2576085604984.
It is an arithmetic number, because the mean of its divisors is an integer number (2576085604984).
Almost surely, 25152171209967 is an apocalyptic number.
5152171209967 is a deficient number, since it is larger than the sum of its proper divisors (1).
5152171209967 is an equidigital number, since it uses as much as digits as its factorization.
5152171209967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2381400, while the sum is 55.
The spelling of 5152171209967 in words is "five trillion, one hundred fifty-two billion, one hundred seventy-one million, two hundred nine thousand, nine hundred sixty-seven".
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