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515315133400447 is a prime number
BaseRepresentation
bin111010100101011010010011…
…1011110010100010101111111
32111120120122102200000110010001
41311022310213132110111333
51020020410343122303242
65023552300521455131
7213354201252102022
oct16512644736242577
92446518380013101
10515315133400447
1113a216a14626366
12499676376414a7
1319170015a97593
149137557ca11b9
153e897e10d6eb7
hex1d4ad2779457f

515315133400447 has 2 divisors, whose sum is σ = 515315133400448. Its totient is φ = 515315133400446.

The previous prime is 515315133400429. The next prime is 515315133400451. The reversal of 515315133400447 is 744004331513515.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-515315133400447 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 515315133400397 and 515315133400406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (515315133410447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257657566700223 + 257657566700224.

It is an arithmetic number, because the mean of its divisors is an integer number (257657566700224).

Almost surely, 2515315133400447 is an apocalyptic number.

515315133400447 is a deficient number, since it is larger than the sum of its proper divisors (1).

515315133400447 is an equidigital number, since it uses as much as digits as its factorization.

515315133400447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512000, while the sum is 46.

The spelling of 515315133400447 in words is "five hundred fifteen trillion, three hundred fifteen billion, one hundred thirty-three million, four hundred thousand, four hundred forty-seven".